[quote]lmjudek wrote:

I’m trying to help a friend with a project… if you have any input, I’d really appreciate it.

She has to build a square, and every side of this square has to be 3 inches in width and height. Each side is of a different thickness though: 1, 3/4, 1/2, 3/8, 1/4, 1/8 inches.

How do you set it up to be a perfect square? [/quote]

Just draw it.

Make the 1" side 3" x 3". Set it flat on the table. This is the “floor” of the box. Now to get each of the walls (which will all be 2" high), subtract the width of each consecutive side from 3". So, this is what you get.

(3/4 side) = 2" x 2-3/4"

(1/2 side) = 2" x 2-1/4"

(3/8 side) = 2" x 2-1/2"

(1/4 side) = 2" x 2-5/8"

now you just add the thicknesses of the opposing walls and subtract those totals from 3" to get the 1/8-thick “roof” dimensions.

so you get (1/8 side) = 1-7/8" x 2-1/4"

again here are those dimensions:

(1" side) = 3" x 3"

(3/4 side) = 2" x 2-3/4"

(1/2 side) = 2" x 2-1/4"

(3/8 side) = 2" x 2-1/2"

(1/4 side) = 2" x 2-5/8"

(1/8 side) = 1-7/8" x 2-1/4"

You can thank me later.