Is the bike’s leverage taken into consideration with the power measurement?
Would the power be measured by the force placed on the pedal, times the distance the pedal travels through one rotation over a certain period of time? I don’t know how the leverage could be taken into the equation though, depending on what gear they’re in.
I’m assuming you’re talking about the power output of just the athlete and not the whole ‘athlete and tool’ used for the competition.
A cyclists power is measured at either the bottom bracket where the cranks attach to frame (SRM) or at the hub of the back wheel(powertap). (there are a couple others, but these two are the most accurate powermeters)
It doesn’t matter, the bikes leverage. The bike doesn’t produce any power itself, its all coming from the riders legs. Leverage is not an issue (it would be if we were only concerned with torque readings at either locations). Power is force x velocity.
I don’t understand what you mean by the “power of the athlete and tool”
Look at it this way. A 200 meter sprinter will only be producing around 500watts at peak speed (after the acceleration) But a top level sprint cyclist will be producing nearly triple that power at peak speed. It simply does not require much power to run at 12m/s. but it takes a ton of power to cycle at 20m/s. (wind resistence is expotenial)
Is that what you mean? The bike allows the athlete to produce more power because the bike is a lever?
That is understood, and the reason why I previously stated that runners do not produce high sustained power.
The purpose of this thread is to find out, simply, what athlete produces the most power of a sprint duration. You need some sort of additional resistence (gravity, wind) to allow the body to produce its maximal power.
I hope this clears things up.