Hi everyone havent done maths since highschool(in third year uni) and am quite stuck on this one problem, I'm probably doing just one thing wrong but cant figure it out

Solve the following linear simultaneous equation systems for y and x.

(a) y = 8x + 4 ; 3y = 2x â?? 6

it would be appreciated if someone could lend a hand

well its easy just put "8x+4" instead of "y" in the second equation ..resolve it that way and then resovle teh first one with teh info gathered..or just give me what a?? is and ill do it for u

OK there are a few ways to solve this. Substitution may be the easiest. if y = 8x + 4 and 3y = 2x "something" 6 we can multiply the left equation by 3. so it becomes 3*y = (3*8)x + (3*4) or for simplicity 3y = 24x + 12 so if we have the other equation we get to replace things. if 3y = 24x +12 and 3y = 2x "something" 6. we can set the two things equal 24x + 12 = 2x "something" 6 so then just solve from there. Hope that helps. post or PM if you have any other questions or if you need more explanation.

= (-84/1) times (1/11) times (1/3) --- (you can rearrange it however you like it doesn't matter) = (-84/3)/11 = -28/11

So, x is -9/11 y is -28/11

If you don't get anything write it out on paper. Doing the problem/solution yourself is usually more helpful in making you understand it than doing mental mathematics, even if you're just copying it. As long as you try to understand it as you rewrite it, you'll get it.