[quote]Chris87 wrote:
[quote]ThugLifeGoldie wrote:
[quote]Chris87 wrote:
[quote]8ProteinLiftW8 wrote:
[quote]ThugLifeGoldie wrote:
I’m a college student, and I do enjoy the occasional (or sometimes more than occasional) drink. However, when I started getting more serious about my training I started making my own concoction in my dorm room from things I get either on campus or in town. After doing some research on making alcohol, I’ve come up with a mixture that has a similar alcohol content to most beers but has significantly fewer calories (my DIY alcohol has about 300 calories per gallon). When I do decide to drink I’ll either only drink that or I’ll start with it to minimize the amount of other alcoholic drinks that I drink later. Anyone is more than welcome to message me if they want the recipe.[/quote]
Alcohol has 7 calories per gram. There are 3785.41 mL in a gallon. Ethanol has a density of 0.789 g/mL. Most beers are 4% alcohol, so 0.043785.41 = the percentage of your gallon that is alcohol, or 151.41 mL. 151.410.789 = the grams of alcohol in your gallon, or 119.46 grams. 119.46*7 = the calories of alcohol in your gallon, or 836.22. This does not include other carbohydrate calories from the grain that you used during distillation. [/quote]
Another way to look at it:
Assuming your 300 calorie claim is true,
300 / 7 calories per gram of alcohol = 42.86 grams of alcohol
14 grams of alcohol is 1 serving (according to the CDC); so
42.86 / 14 = 3.06 serving of alcohol in your gallon of drink
So either your drink has almost no alcohol whatsoever and wouldn’t get a puppy drunk, or you miscalculated somewhere along the line.[/quote]
LOL whoops. It has gotten me pretty fucked up, so I’m gonna have to assume I screwed up the math. Never was too good at math anyway -__-. Anyway, I think (not 100% sure anymore after having just been mathematically and scientifically shat on) that the calorie content is still lower than what college kids usually drink. Here’s my math if anyone wants to find the mistake and correct it:
72 packets of sugar (each packet is about 2 to 4 grams)=288 grams of sugar (assuming the high end)=288 grams of alcohol after the yeast eats the sugar and releases the waste products (conservation of matter, I know some of the reaction gets released as CO2 so really somewhere south of 288 but no idea where)=less than 41.14 calories from alcohol
10 packets of Emergen-C powder for flavoring (sugar water is fucking disgusting+I’m a pussy LOL) and for the nutrients (lessen the dehydrating effect, therefore preventing/lessening the effect of hangovers. I also hypothesize that the Vitamin C helps to prevent/lessen vomiting but I have absolutely no evidence to prove it). 25 calories per packet X 10 packets=250 calories from Emergen-C
250 calories from Emergen-C + 41.14 calories from alcohol=something less than 291.14 calories per gallon (but we don’t know how much less). Granted, it’s an extremely amateurish and low quality mixture (I don’t have any way of distilling it in my dorm room, so I end up drinking the dregs. Yuck!). Do my math and science make sense? Since, now admittedly, it probably doesn’t, where are my mistake(s)?[/quote]
Alcohol is 7 calories per gram,
So if we assume there is 288 grams of alcohol (which sounds reasonable to me),
288 * 7 = 2,016
Add in the 250 calories from Emergen-C and you get ~2,250 calories total
288 grams of alcohol / 14 grams of alcohol in 1 serving = ~20.5 servings
2,250 calories total / 20.5 servings = ~110 calories per serving of alcohol
110 calories per serving is on par with most light beers[/quote]
Oh whoops I divided grams/calories instead of multiplying grams X calories. Thanks man.